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x^2-6.7x+9.9=0
a = 1; b = -6.7; c = +9.9;
Δ = b2-4ac
Δ = -6.72-4·1·9.9
Δ = 5.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.7)-\sqrt{5.29}}{2*1}=\frac{6.7-\sqrt{5.29}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.7)+\sqrt{5.29}}{2*1}=\frac{6.7+\sqrt{5.29}}{2} $
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